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0.7=1.3x+x^2
We move all terms to the left:
0.7-(1.3x+x^2)=0
We get rid of parentheses
-x^2-1.3x+0.7=0
We add all the numbers together, and all the variables
-1x^2-1.3x+0.7=0
a = -1; b = -1.3; c = +0.7;
Δ = b2-4ac
Δ = -1.32-4·(-1)·0.7
Δ = 4.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{4.49}}{2*-1}=\frac{1.3-\sqrt{4.49}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{4.49}}{2*-1}=\frac{1.3+\sqrt{4.49}}{-2} $
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